public class Test { }What is the prototype of the default constructor?...
Option A and B are wrong because they use the default access modifier and the access modifier for the class is public (remember, the default constructor has the same access modifier as the class).
Option D is wrong. The void makes the compiler think that this is a method specification - in fact if it were a method specification the compiler would spit it out.
public class Test { }What is the prototype of the default constructor?...
Understanding the Default Constructor
In Java, a default constructor is a constructor that does not take any parameters. It is automatically provided by the compiler if no other constructors are explicitly defined in the class.
Prototype of the Default Constructor
- The correct answer is option 'C': public Test().
- This prototype indicates that the constructor is public, meaning it can be accessed from outside the class, and it does not take any parameters.
Why Other Options are Incorrect
- Option A: Test()
- This is a valid constructor declaration, but it lacks the access modifier. Constructors should be defined with an access modifier (like public) to clearly indicate their accessibility.
- Option B: Test(void)
- In Java, constructors do not use the `void` keyword. This syntax is incorrect as constructors are defined without any return type.
- Option D: public Test(void)
- Similar to option B, using `void` is incorrect in the context of a constructor. Constructors are defined without any return type, not even void.
Conclusion
The correct prototype for a default constructor in Java is public Test(). This allows instances of the class to be created without passing any parameters, adhering to Java's syntax rules regarding constructors. Thus, option 'C' is the accurate choice.